Sue Makkoo Wiki – She is a well-known personality already and people have been interested in knowing about her, but today suddenly the whole world is searching for Sue.
The entire social media is full of stuff related to her. Some want to know about her personal life like her family, her net worth, her income, and some want to know about her professional life. Here “A Real News” has come out with a whole bunch of information.
Who is Sue Makkoo?
She is a famous American designer and costume director. And she is the girlfriend of Ariana DeBose, she is a popular American actress. If you wanna more details about Sue Makkoo Wiki, Husband, Wiki, Daughter then Continue reading this article and know all details.
Sue Makkoo Wiki (Early Life, Age)
Sue was born on 16 February 1971 and born in New York, United States. Now she was 51 years old in 2022. Her real name is Sue Makkoo. By profession, She is a famous American designer and costume director. If you wanna more details about Sue Makkoo Wiki then Continue reading this article.
Sue Makkoo Bio, Age, Profession, Height, Weight
|Full Name||Sue Makkoo|
|Profession||Designer and Costume director|
|Husband name||Not Known|
|Girlfriend name||Ariana DeBose|
|Weight (Approx)||70 kg|
|Date of Birth||13 December 1989|
|Birth Place||New York, United States|
|Zodiac sign||Not Known|
|School Name||Private School|
|College Name||Arizona State University|
|Father Name||Not Known|
|Mother Name||Not Known|
|Source Of Income||Designer and Costume director|
|Net Worth||$10 million (Approx)|
Sue Makkoo Biography, Education Qualification
She was born in New York, United States. Now she was 51 years old in 2021. She was an American Designer and Costume director. She completed her school education at Private School and she completed her college education at Arizona State University. If you have known more info about Sue Makkoo Wiki, Parents, Relationships, Children, and more then continue reading this article.
Sue Makkoo Parents (Father, Mother Name)
Sue is an American Designer and Costume director. She founded Maney Saving. She was 51 years old. Her father’s name and her mother’s names are not known. Her sibling’s names are not mentioned in this article. She was don’t share personal information on Social Media. So all Fans keep reading this article and know all details about Sue Makkoo Wiki.
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Sue Makkoo Career, Profession, Ethnicity
Sue was born on 16 February 1971 and born in New York, United States. Now she was 51 years old in 2022. She is a famous American designer and costume director. And she is the girlfriend of Ariana DeBose, she is a popular American actress. Sue worked as an Assistant Professor of Costume Design at Colorado Christian University.
After that, she has worked as a Costume Designer at La Jolla Playhouse and later Sue Makkoo worked as a Wardrobe Manager at RWS Entertainment Group. She also worked as a Faculty at Manhattan School of Music and later Sue Makkoo became a Freelance Costume Designer.
Sue Makkoo then worked as a Costume Associate at Summer: The Donna Summer Musical Broadway and since February 2016 she is working as a Freelance Interior Designer. Her ethnicity is not known. If you want to know more information about Sue Makkoo Wiki then keep reading this article.
Sue Makkoo Husband, Children
- Her marital status is married her husband’s name is not known.
|Girlfriend Name||Ariana DeBose|
|Father’s Name||Not Known|
|Mother’s Name||Not Known|
|Marriage Date||Not Known|
Sue Makkoo Social link Instagram, Twitter
Sue Some Amazing Facts
- She is an American designer and costume director.
- She is Famous as an American-based designer.
- She has more followers on Instagram’s Official Account.
- Sue loves her mom a lot.
- Sue mostly loved her Son.
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FAQ About Sue Makkoo
Q. Who is Sue Makkoo?
Ans. She is an American Designer and Costume director.
Q. What is the name of the Father of Sue?
Ans. Not Known.
Q. How old is Sue?
Ans. She is 51 years old in 2021.
Q. What is the birthplace of Sue?
Ans. Sue Makkoo’s birthplace is New York, United States.
Q. What was the name of Sue’s Husband?
Ans. Not Known.
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